in the exercise below, you will determine the traits of a fictitious creature called the snork. snorks were discovered on the planet dee enae, and they have a very small genome - just one chromosome that contains six genes. below is the dna of one snork.
step 1 transcribe each gene below by matching it with the correct mrna
column a
1 gene 1: tac aac ggt cat
a mrna: aug uug cca gua
2 gene 2: atc cga tcg
b mrna: uag gcu agc
3 gene 3: ttt aag aaa
c mrna: aaa uuc uuu
4 gene 4: gga ctc cga
d mrna: ccu gag gcu
5 gene 5: ccg aca aaa
e mrna: ggc ugu uuu
6 gene 6: atc atc cga
f mrna: uag uag gcu

Question

Accepted Answer

# Explanation:
## Step1: Recall Transcription Rules
During transcription, DNA's thymine (T) pairs with mRNA's adenine (A), adenine (A) pairs with uracil (U), cytosine (C) pairs with guanine (G), and guanine (G) pairs with cytosine (C).

## Step2: Transcribe Gene 1 (TAC AGC GGT CAT)
- TAC → AUG, AGC → UCG, GGT → CCA, CAT → GUA. Wait, no, let's check the options. Wait, maybe I misread. Wait, the options: Let's take Gene 1: TAC AGC GGT CAT. Replace T with U? No, wait, DNA to mRNA: T→A, A→U, C→G, G→C. So TAC (DNA) → AUG (mRNA)? Wait, no, the options have, for example, option a: mRNA: AUG UCG CCA GUA. Wait, Gene 1: TAC AGC GGT CAT. So TAC→AUG, AGC→UCG, GGT→CCA, CAT→GUA. So that's option a. Wait, but let's check each:

1. Gene 1: TAC AGC GGT CAT. Transcribe: T→A, A→U, C→G, G→C. So TAC→AUG, AGC→UCG, GGT→CCA, CAT→GUA. So mRNA: AUG UCG CCA GUA (matches option a? Wait, option a is "mRNA: AUG UCG CCA GUA"? Wait, the user's option a: "mRNA: AUG UCG CCA GUA"? Let's check:

Gene 1: TAC AGC GGT CAT.

TAC → AUG (T→A, A→U, C→G? Wait no: DNA base: T, A, C, G. mRNA base: A, U, G, C. So T (DNA) pairs with A (mRNA), A (DNA) pairs with U (mRNA), C (DNA) pairs with G (mRNA), G (DNA) pairs with C (mRNA). So TAC (DNA) is T-A-C. So mRNA: A-U-G? Wait no: T (DNA) → A (mRNA), A (DNA) → U (mRNA), C (DNA) → G (mRNA). So TAC (DNA) → AUG (mRNA). Then AGC (DNA): A→U, G→C, C→G → UCG (mRNA). GGT (DNA): G→C, G→C, T→A → CCA (mRNA). CAT (DNA): C→G, A→U, T→A → GUA (mRNA). So mRNA: AUG UCG CCA GUA. So that's option a. So Gene 1 matches option a.

2. Gene 2: ATC CGA TGG. DNA: ATC CGA TGG. Transcribe: A→U, T→A, C→G; C→G, G→C, A→U; T→A, G→C, G→C. So ATC→UAG, CGA→GCU, TGG→ACC? Wait no, wait the option b: mRNA: UAG GCU ACC? Wait, no, option b is "mRNA: UAG GCU ACC"? Wait, maybe I made a mistake. Wait, the Gene 2 is ATC CGA TGG. Let's do each triplet: ATC (DNA) → UAG (mRNA: A→U, T→A, C→G), CGA (DNA: C→G, G→C, A→U) → GCU (mRNA), TGG (DNA: T→A, G→C, G→C) → ACC (mRNA). So mRNA: UAG GCU ACC. But option b is "mRNA: UAG GCU ACC"? Wait, option b is "mRNA: UAG GCU ACC"? Let's check the options. The user's option b: "mRNA: UAG GCU ACC"? Wait, maybe the Gene 2 is ATC CGA TGG, so transcription gives UAG GCU ACC, which is option b? Wait, no, the option b is "mRNA: UAG GCU ACC"? Let's proceed.

3. Gene 3: TTT AAA AAA. DNA: TTT AAA AAA. Transcribe: T→A, T→A, T→A; A→U, A→U, A→U; A→U, A→U, A→U. So mRNA: AAA UUU UUU. Wait, option f: "mRNA: AAA UUU UUU"? Let's check. Gene 3: TTT AAA AAA. TTT→AAA (T→A), AAA→UUU (A→U), AAA→UUU (A→U). So mRNA: AAA UUU UUU. So that's option f.

4. Gene 4: GGA CTC CGA. DNA: GGA CTC CGA. Transcribe: G→C, G→C, A→U; C→G, T→A, C→G; C→G, G→C, A→U. So GGA→CCU, CTC→GAG, CGA→GCU? Wait no, option d: "mRNA: CCU GAG GCU"? Let's check. GGA (DNA): G→C, G→C, A→U → CCU (mRNA). CTC (DNA): C→G, T→A, C→G → GAG (mRNA). CGA (DNA): C→G, G→C, A→U → GCU (mRNA). So mRNA: CCU GAG GCU. Which is option d. So Gene 4 matches option d.

5. Gene 5: TGG ACG AAA. DNA: TGG ACG AAA. Transcribe: T→A, G→C, G→C; A→U, C→G, G→C; A→U, A→U, A→U. So TGG→ACC, ACG→UGC, AAA→UUU. Wait, option e: "mRNA: ACC UGC UUU"? Let's check. TGG (DNA): T→A, G→C, G→C → ACC (mRNA). ACG (DNA): A→U, C→G, G→C → UGC (mRNA). AAA (DNA): A→U, A→U, A→U → UUU (mRNA). So mRNA: ACC UGC UUU. Which is option e. So Gene 5 matches option e.

6. Gene 6: ATC ATC CGA. DNA: ATC ATC CGA. Transcribe: A→U, T→A, C→G; A→U, T→A, C→G; C→G, G→C, A→U. So ATC→UAG, ATC→UAG, CGA→GCU. Wait, option c: "mRNA: UAG UAG GCU"? Let's check. ATC (DNA) → UAG (mRNA: A→U, T→A, C→G), ATC→UAG, CGA→GCU (C→G, G→C, A→U). So mRNA: UAG UAG GCU. Which is option c. So Gene 6 matches option c.

Wait, but the problem is to match each gene with the correct mRNA. So the answers would be:

1. Gene 1 → a

2. Gene 2 → b (Wait, Gene 2: ATC CGA TGG. Let's recheck. ATC (DNA) → UAG (mRNA), CGA (DNA) → GCU (mRNA), TGG (DNA) → ACC (mRNA). So mRNA: UAG GCU ACC. Which is option b: "mRNA: UAG GCU ACC"? Yes. So Gene 2 matches option b.

3. Gene 3 → f (mRNA: AAA UUU UUU)

4. Gene 4 → d (mRNA: CCU GAG GCU)

5. Gene 5 → e (mRNA: ACC UGC UUU)

6. Gene 6 → c (mRNA: UAG UAG GCU)

But the problem has 6 genes? Wait, the user's table has 6 genes? Wait, the user's image shows:

Column A:

1. Gene 1: TAC AGC GGT CAT

2. Gene 2: ATC CGA TGG

3. Gene 3: TTT AAA AAA

4. Gene 4: GGA CTC CGA

5. Gene 5: TGG ACG AAA

6. Gene 6: ATC ATC CGA

Column B:

a. mRNA: AUG UCG CCA GUA

b. mRNA: UAG GCU ACC

c. mRNA: UAG UAG GCU

d. mRNA: CCU GAG GCU

e. mRNA: ACC UGC UUU

f. mRNA: AAA UUU UUU

So the matches are:

1. Gene 1 → a

2. Gene 2 → b

3. Gene 3 → f

4. Gene 4 → d

5. Gene 5 → e

6. Gene 6 → c

# Answer:
1. a
2. b
3. f
4. d
5. e
6. c

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QUESTION IMAGE

Question

Explanation:

Step1: Recall Transcription Rules

Step2: Transcribe Gene 1 (TAC AGC GGT CAT)

Answer: