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Question
example 2: using the segment addition postulate. ac = 3x + 3, ab=-1 + 2x, and bc = 11. find x. 8. ad = -7 -7 units 7 7 units
Step1: Apply segment - addition postulate
Since on a line segment $AC = AB+BC$, we substitute the given expressions: $3x + 3=(-1 + 2x)+11$.
Step2: Simplify the right - hand side
$(-1 + 2x)+11=2x+(-1 + 11)=2x + 10$. So the equation becomes $3x + 3=2x + 10$.
Step3: Solve for $x$
Subtract $2x$ from both sides: $3x-2x+3=2x-2x + 10$, which gives $x+3=10$. Then subtract 3 from both sides: $x=10 - 3=7$.
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$x = 7$