QUESTION IMAGE
Question
example (do this one yourself)
a student wants to airdrop a food parcel to the stranded person on the island:
- draw the trajectory of the food parcel
- calculate the time to land
- calculate where she should release the parcel.
practice problems
- on the diagrams below, draw vectors showing:
the acceleration (left diagram)
the total velocity
the vertical component of velocity
the horizontal component of velocity
- a boy and girl are climbing a tree. the girl is 10 m above the ground and throws a ball horizontally at 18 ms^{-1}. the boy is 12 m above the ground and can only throw her ball horizontally at 15 ms^{-1}. whose ball lands furthest from the tree?
Identify given values
We analyze the "EXAMPLE (DO THIS ONE YOURSELF)" problem.
- Initial horizontal velocity: \(u_x = 100\text{ m s}^{-1}\)
- Initial vertical velocity: \(u_y = 0\text{ m s}^{-1}\)
- Vertical displacement: \(s_y = -500\text{ m}\) (downward)
- Acceleration due to gravity: \(g = 9.8\text{ m s}^{-2}\) (downward)
Calculate time to land
We use the vertical kinematic equation:
Since \(u_y = 0\) and \(a_y = -g\):
Calculate release position
We find the horizontal distance (range) traveled during this time:
She should release the parcel at a horizontal distance of \(1010\text{ m}\) before reaching the island.
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Question 1
- Draw the trajectory of the food parcel: The trajectory is a parabolic curve starting horizontally from the plane and curving downwards to the stranded person on the island (as indicated by the dashed line in the diagram).
- Calculate the time to land: <blank>\(10.1\text{ s}\)</blank> (using \(g = 9.8\text{ m s}^{-2}\)) or <blank>\(10\text{ s}\)</blank> (using \(g = 10\text{ m s}^{-2}\)).
- Calculate where she should release the parcel: <blank>\(1010\text{ m}\)</blank> (using \(g = 9.8\text{ m s}^{-2}\)) or <blank>\(1000\text{ m}\)</blank> (using \(g = 10\text{ m s}^{-2}\)) horizontally before the island.