Question

1. examine the free body diagram shown above. what is the magnitude of the net force on this object? 21 n 265 n 131 n 76 n

Explanation:

Step1: Calculate net force in vertical direction

Forces in vertical direction: \(F_{y1} = 67N\) (upward), \(F_{y2}=67N\) (downward). Net vertical force \(F_y=F_{y1}-F_{y2}=67 - 67=0N\)

Step2: Calculate net force in horizontal direction

Forces in horizontal direction: \(F_{x1} = 76N\) (right - ward), \(F_{x2}=55N\) (left - ward). Net horizontal force \(F_x=F_{x1}-F_{x2}=76 - 55 = 21N\)

Step3: Calculate the net force

Since \(F_y = 0N\), the net force \(F=\sqrt{F_x^{2}+F_y^{2}}=\sqrt{21^{2}+0^{2}}=21N\)

Answer:

21 N