Question

1. everyone in squidwards family has light blue skin, which is the dominant trait for body color in his hometown of squid valley. his family brags that they are a \purebred\ line. he recently married a nice girl who has light green skin, which is a recessive trait. create a punnett square to show the possibilities that would result if squidward and his new bride had children. use b to represent the dominant gene and b to represent the recessive gene. purebred = homozygous

a. list the possible genotypes and phenotypes for their children.
b. what are the chances of a child with light blue skin? ____%
c. what are the chances of a child with light green skin? ____%
d. would squidwards children still be considered purebreds? explain!

Explanation:

Step1: Determine the genotypes of Squidward and his bride

Since Squidward's family is pure - bred (homozygous) for the dominant light - blue skin trait, his genotype is \(BB\). His bride has light - green skin (recessive trait), so her genotype is \(bb\).

Step2: Create the Punnett square

	\(B\)	\(B\)
\(b\)	\(Bb\)	\(Bb\)

Step3: Analyze genotypes and phenotypes (for part A)

All of their children will have the genotype \(Bb\). Since \(B\) (light - blue) is dominant over \(b\) (light - green), all children will have the phenotype of light - blue skin.

Step4: Calculate probabilities (for parts B and C)

Since all 4 boxes in the Punnett square are \(Bb\) (light - blue), the probability of a child with light - blue skin (\(P(Bb)\)) is \(\frac{4}{4}=1 = 100\%\). The probability of a child with light - green skin (\(P(bb)\)) is \(\frac{0}{4}=0 = 0\%\)

Step5: Determine pure - bred status (for part D)

Pure - bred means homozygous (\(BB\) or \(bb\)). Since all children have the genotype \(Bb\) (heterozygous), they are not pure - bred.

Answer:

A. Genotype: \(Bb\) for all children; Phenotype: All have light - blue skin.
B. \(100\%\)
C. \(0\%\)
D. No. Because their genotype is \(Bb\) (heterozygous), not homozygous (\(BB\) or \(bb\)).