Question

evaluate. write your answers as fractions.
$\frac{3^{2}}{-2}=$
$ - (\frac{3}{2})^{3}=$

Explanation:

Step1: Calculate $3^2$

$3^2=3\times3 = 9$

Step2: Calculate $\frac{3^2}{-2}$

$\frac{3^2}{-2}=\frac{9}{-2}=-\frac{9}{2}$

Step3: Calculate $(\frac{3}{2})^3$

$(\frac{3}{2})^3=\frac{3}{2}\times\frac{3}{2}\times\frac{3}{2}=\frac{3\times3\times3}{2\times2\times2}=\frac{27}{8}$

Step4: Calculate $-(\frac{3}{2})^3$

$-(\frac{3}{2})^3=-\frac{27}{8}$

Answer:

$-\frac{9}{2},-\frac{27}{8}$