Question

evaluate (\frac{1}{2}t + \frac{3}{8}) when (t = \frac{1}{4}).

Explanation:

Step1: Substitute \( t = \frac{1}{4} \) into the expression

We have the expression \( \frac{1}{2}t + \frac{3}{8} \). Substitute \( t = \frac{1}{4} \), so it becomes \( \frac{1}{2} \times \frac{1}{4} + \frac{3}{8} \).

Step2: Calculate the multiplication

\( \frac{1}{2} \times \frac{1}{4} = \frac{1 \times 1}{2 \times 4} = \frac{1}{8} \). Now the expression is \( \frac{1}{8} + \frac{3}{8} \).

Step3: Add the fractions

Since the denominators are the same, we add the numerators: \( \frac{1 + 3}{8} = \frac{4}{8} \). Simplify \( \frac{4}{8} \) to \( \frac{1}{2} \).

Answer:

\( \frac{1}{2} \)