Question

evaluate the expression if (x = 6), (y = 8), and (z = 3). (z^{2}+(y^{2}-4x))

Explanation:

Step1: Substitute the values

Substitute $x = 6$, $y = 8$, and $z = 3$ into the expression $z^{3}+(y^{2}-4x)$.
$3^{3}+(8^{2}-4\times6)$

Step2: Calculate the powers and multiplications

First, calculate $3^{3}=3\times3\times3 = 27$, $8^{2}=8\times8 = 64$, and $4\times6 = 24$.
$27+(64 - 24)$

Step3: Calculate the subtraction inside the parentheses

$64-24=40$.
$27 + 40$

Step4: Calculate the final sum

$27+40 = 67$

Answer:

67