Question

evaluate each expression.

1. $(-5)^0 - 3$
2. $3 - 4 \times -3$

Explanation:

Problem 20: $(-5)^{\circ} - 3$ (Assuming it's $(-5)^0 - 3$ as $0$ exponent is common, maybe a typo)

Step1: Evaluate the exponent

Any non - zero number to the power of 0 is 1. So $(-5)^0 = 1$.

Step2: Subtract 3

Now we have $1-3=-2$.

Step1: Perform the multiplication

According to the order of operations (PEMDAS/BODMAS), we multiply first. $4\times(-3)=-12$, but since there is a negative sign in front of the 3 in the multiplication, we have $-4\times(-3) = 12$ (because the product of two negative numbers is positive).

Step2: Perform the subtraction (or addition in this case)

Now we add 3 and 12 (since $3-4\times(-3)=3 + 12$). $3+12 = 15$.

Answer:

-2

Problem 22: $3 - 4\times(-3)$