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7. at the equator, the earth spins a distance of 41,830,069 m every day…

Question

  1. at the equator, the earth spins a distance of 41,830,069 m every day. calculate the average speed of the earth in m/s.

Explanation:

Step1: Calculate the total number of seconds in a day

There are \(24\) hours in a day, \(60\) minutes in an hour and \(60\) seconds in a minute. So the number of seconds in a day \(t=24\times60\times60\) s.

$$t = 86400\space s$$

Step2: Use the speed formula \(v=\frac{s}{t}\)

Given \(s = 41830069\space m\) and \(t=86400\space s\). Then \(v=\frac{41830069}{86400}\)

$$v=\frac{41830069}{86400}\approx484.14\space m/s$$

Answer:

The average speed of the Earth is approximately \(484.14\space m/s\)