Question

the equation $c = \frac{13}{v}$ shows that the density of a particular substance equals a ratio of 13 grams divided by the volume of the substance. what happens to the density as the volume approaches 0?

• the density approaches infinity.
• the density approaches 0.
• the density approaches 1.
• the density approaches 13.

Explanation:

Step1: Analyze the function

The density function is \( C=\frac{13}{V} \), where \( C \) is density and \( V \) is volume. We need to find the limit of \( C \) as \( V \to \infty \).

Step2: Evaluate the limit

For a function of the form \( y = \frac{k}{x} \) (where \( k \) is a constant), as \( x \to \infty \), the value of \( y \) approaches 0. Here, \( k = 13 \) and \( x = V \). So, as \( V \to \infty \), \( \frac{13}{V} \to 0 \). Thus, the density \( C \) approaches 0.

Answer:

The density approaches 0. (Corresponding option: The option with "The density approaches 0.")