Question

the engines of a plane are pushing it 450 mph east, but the wind is blowing it 80° south of west at 25 mph. what is the direction of the planes resultant vector? measure the angle from the positive x - axis. |\overrightarrow{r}| = 446.34 mph \theta = ?^\circ

Explanation:

Step1: Resolve vectors into components

The plane's velocity vector (let's call it \(\vec{P}\)) is 450 mph east, so in component form, \(\vec{P} = \langle 450, 0
angle\) (since east is the positive x - direction and there is no y - component).

The wind is blowing 80° south[SSE Completed, Client Connection Error][SSE Completed, Client Connection Error][LLM SSE On Failure]

Answer:

Step1: Resolve vectors into components

The plane's velocity vector (let's call it \(\vec{P}\)) is 450 mph east, so in component form, \(\vec{P} = \langle 450, 0
angle\) (since east is the positive x - direction and there is no y - component).

The wind is blowing 80° south[SSE Completed, Client Connection Error][SSE Completed, Client Connection Error][LLM SSE On Failure]