Question

1. electricity what is the voltage v of an electric circuit with a current c of 2 - j and an impedance i of 3 + 2j? use the formula v = ci.

8 + j
6 - 2j
4 + j
5 + j

Explanation:

Step1: Substitute values into formula

Given $C = 2 - j$ and $I=3 + 2j$, and $V = CI$. So $V=(2 - j)(3 + 2j)$.

Step2: Expand the product

Using the FOIL method: $V = 2\times3+2\times2j - j\times3 - j\times2j=6 + 4j-3j - 2j^{2}$.

Step3: Simplify using $j^{2}=- 1$

Since $j^{2}=-1$, then $V = 6 + 4j-3j-2\times(-1)=6 + 4j-3j + 2$.

Step4: Combine like - terms

$V=(6 + 2)+(4j-3j)=8 + j$.

Answer:

$8 + j$