Question

for each value of y, determine whether it is a solution to 39 ≥ 6y - 9.

y	is it a solution?
7	∘ (yes)	∘ (no)
-3	∘ (yes)	∘ (no)
2	∘ (yes)	∘ (no)

Explanation:

Step1: For \( y = 6 \)

Substitute \( y = 6 \) into \( 39\geq8y - 9 \).
Calculate \( 8y-9 = 8\times6 - 9 = 48 - 9 = 39 \).
Since \( 39\geq39 \) is true, \( y = 6 \) is a solution.

Step2: For \( y = 7 \)

Substitute \( y = 7 \) into \( 39\geq8y - 9 \).
Calculate \( 8y - 9 = 8\times7 - 9 = 56 - 9 = 47 \).
Since \( 39\geq47 \) is false, \( y = 7 \) is not a solution.

Step3: For \( y = - 3 \)

Substitute \( y=-3 \) into \( 39\geq8y - 9 \).
Calculate \( 8y - 9 = 8\times(-3)-9=-24 - 9=-33 \).
Since \( 39\geq - 33 \) is true, \( y = - 3 \) is a solution.

Step4: For \( y = 2 \)

Substitute \( y = 2 \) into \( 39\geq8y - 9 \).
Calculate \( 8y - 9 = 8\times2-9 = 16 - 9 = 7 \).
Since \( 39\geq7 \) is true, \( y = 2 \) is a solution.

Answer:

• For \( y = 6 \): Yes
• For \( y = 7 \): No
• For \( y=-3 \): Yes
• For \( y = 2 \): Yes