QUESTION IMAGE
Question
- each tire of a three-wheeled electric vehicle (tuk-tuk) has a \\(12\text{cm} \times 8\text{cm}\\) area touching the ground. the mass of the vehicle is \\(240\text{ kg}\\) and it carries a driver and passengers with a total mass of \\(180\text{ kg}\\). find the minimum pressure needed in the tires. (take \\(g = 10\text{ms}^{-2}\\)) (4-marks)
<pre_analysis>
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</pre_analysis>
<reasoning>
Calculate total mass and weight
Find the total mass \(M\) and total downward force \(F\).
\[
M = 240\text{ kg} + 180\text{ kg} = 420\text{ kg}
\]
\[
F = M \cdot g = 420\text{ kg} \times 10\text{ ms}^{-2} = 4200\text{ N}
\]
Calculate total contact area
Find the total area \(A\) of all three tires.
\[
A_{\text{one}} = 12\text{ cm} \times 8\text{ cm} = 96\text{ cm}^2 = 96 \times 10^{-4}\text{ m}^2
\]
\[
A = 3 \times A_{\text{one}} = 3 \times 96 \times 10^{-4}\text{ m}^2 = 0.0288\text{ m}^2
\]
Calculate minimum tire pressure
Apply the pressure formula \(P = \frac{F}{A}\).
\[
P = \frac{4200\text{ N}}{0.0288\text{ m}^2} \approx 145833.33\text{ Pa}
\]
\[
P \approx 1.46 \times 10^5\text{ Pa}
\]
</reasoning>
<answer>
\(1.46 \times 10^5\text{ Pa}\) (or \(145.83\text{ kPa}\))
</answer>
<post_analysis>
{
"subject": "Natural Science",
"question_type": "Word Problem",
"knowledge_point": [
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]
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</post_analysis>
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<pre_analysis>
{
"quality": "clear",
"question_count": 1,
"skills_matched": [
"step_cot",
"explain_then_answer",
"tutor"
],
"needs_drawing": false,
"concepts_used": [],
"new_concepts": [
"Pressure in Fluids",
"Force and Area"
],
"current_concepts": [
"Pressure in Fluids",
"Force and Area",
"Weight Calculation"
]
}
</pre_analysis>
<reasoning>
Calculate total mass and weight
Find the total mass \(M\) and total downward force \(F\).
\[
M = 240\text{ kg} + 180\text{ kg} = 420\text{ kg}
\]
\[
F = M \cdot g = 420\text{ kg} \times 10\text{ ms}^{-2} = 4200\text{ N}
\]
Calculate total contact area
Find the total area \(A\) of all three tires.
\[
A_{\text{one}} = 12\text{ cm} \times 8\text{ cm} = 96\text{ cm}^2 = 96 \times 10^{-4}\text{ m}^2
\]
\[
A = 3 \times A_{\text{one}} = 3 \times 96 \times 10^{-4}\text{ m}^2 = 0.0288\text{ m}^2
\]
Calculate minimum tire pressure
Apply the pressure formula \(P = \frac{F}{A}\).
\[
P = \frac{4200\text{ N}}{0.0288\text{ m}^2} \approx 145833.33\text{ Pa}
\]
\[
P \approx 1.46 \times 10^5\text{ Pa}
\]
</reasoning>
<answer>
\(1.46 \times 10^5\text{ Pa}\) (or \(145.83\text{ kPa}\))
</answer>
<post_analysis>
{
"subject": "Natural Science",
"question_type": "Word Problem",
"knowledge_point": [
"Natural Science",
"Physics",
"Pressure in Fluids"
]
}
</post_analysis>