QUESTION IMAGE
Question
for each problem, find the x - and y - intercepts, x - coordinates of the critical points, open intervals where the function is increasing and decreasing, x - coordinates of the inflection points, open intervals where the function is concave up and concave down, and relative minima and maxima. using this information, sketch the graph of the function.
y = -\frac{x^4}{4}+x^2
Step1: Find the \(y -\)intercept
Set \(x = 0\) in \(y=-\frac{x^{3}}{3}+x^{2}\). Then \(y=-\frac{0^{3}}{3}+0^{2}=0\). So the \(y -\)intercept is \((0,0)\).
Step2: Find the first - derivative
Differentiate \(y =-\frac{x^{3}}{3}+x^{2}\) using the power rule \(y^{\prime}=-x^{2}+2x=-x(x - 2)\).
Step3: Find the critical points
Set \(y^{\prime}=0\), so \(-x(x - 2)=0\). Solving for \(x\), we get \(x = 0\) and \(x = 2\).
Step4: Determine the intervals of increase and decrease
- For \(x<0\), let \(x=-1\), then \(y^{\prime}=-(-1)(-1 - 2)=-3<0\). So the function is decreasing on \((-\infty,0)\).
- For \(0
- For \(x>2\), let \(x = 3\), then \(y^{\prime}=-3(3 - 2)=-3<0\). So the function is decreasing on \((2,\infty)\).
Step5: Find the relative minima and maxima
- Since the function changes from decreasing \((x<0)\) to increasing \((0<x<2)\) at \(x = 0\), \(y(0)=0\) is a relative minimum.
- Since the function changes from increasing \((0<x<2)\) to decreasing \((x>2)\) at \(x = 2\), \(y(2)=-\frac{8}{3}+4=\frac{4}{3}\) is a relative maximum.
Step6: Find the second - derivative
Differentiate \(y^{\prime}=-x^{2}+2x\). \(y^{\prime\prime}=-2x + 2=-2(x - 1)\).
Step7: Find the inflection point
Set \(y^{\prime\prime}=0\), then \(-2(x - 1)=0\), so \(x = 1\). When \(x = 1\), \(y=-\frac{1}{3}+1=\frac{2}{3}\). The inflection point is \((1,\frac{2}{3})\).
Step8: Determine the concavity
- For \(x<1\), let \(x = 0\), then \(y^{\prime\prime}=-2(0 - 1)=2>0\). The function is concave up on \((-\infty,1)\).
- For \(x>1\), let \(x = 2\), then \(y^{\prime\prime}=-2(2 - 1)=-2<0\). The function is concave down on \((1,\infty)\).
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- \(y -\)intercept: \((0,0)\)
- Critical points: \(x = 0\) (relative minimum, \(y = 0\)) and \(x = 2\) (relative maximum, \(y=\frac{4}{3}\))
- Intervals of increase: \((0,2)\)
- Intervals of decrease: \((-\infty,0)\cup(2,\infty)\)
- Inflection point: \((1,\frac{2}{3})\)
- Concave up: \((-\infty,1)\)
- Concave down: \((1,\infty)\)