Question

in a drill during basketball practice, a player runs the length of a 30.0 meter court and back. the player does this three times in 60 seconds. (image: basketball court with 30. m, labeled \(not drawn to scale)\) the average speed of the player during the drill is... options: a 0.0 m/s, b 0.50 m/s, c 3.0 m/s, d 30 m/s

Explanation:

Step1: Calculate total distance

The player runs 30.0 m to the end and 30.0 m back, so one round trip is \( 30.0 + 30.0 = 60.0 \) m.
Doing this three times, total distance \( d = 3 \times 60.0 = 180.0 \) m.

Step2: Use speed formula

Average speed \( v = \frac{d}{t} \), where \( t = 60 \) s.
So \( v = \frac{180.0}{60} = 3.0 \) m/s.

Answer:

C. 3.0 m/s