Question

draw the image of quadrilateral abcd under a translation by 1 unit to the right and 6 units up.

Explanation:

Step1: Recall translation rule

For a point $(x,y)$ translated 1 unit to the right and 6 units up, the new point is $(x + 1,y+6)$.

Step2: Find new coordinates of point A

If point A has coordinates $(1,-4)$, then new - A: $(1 + 1,-4 + 6)=(2,2)$.

Step3: Find new coordinates of point B

If point B has coordinates $(-6,-2)$, then new - B: $(-6 + 1,-2+6)=(-5,4)$.

Step4: Find new coordinates of point C

If point C has coordinates $(-5,1)$, then new - C: $(-5 + 1,1 + 6)=(-4,7)$.

Step5: Find new coordinates of point D

If point D has coordinates $(0,-2)$, then new - D: $(0 + 1,-2+6)=(1,4)$.

Step6: Draw new quadrilateral

Plot the new points $(2,2),(-5,4),(-4,7),(1,4)$ and connect them in order to form the image of quadrilateral ABCD.

Answer:

Plot points $(2,2),(-5,4),(-4,7),(1,4)$ and connect them to get the translated quadrilateral.