Question

draw the image of △abc under the translation (x,y)→(x,y + 3).

Explanation:

Step1: Identify coordinates of vertices

Let's assume the coordinates of \(A\) are \((- 5,-3)\), \(B\) are \((0,0)\) and \(C\) are \((-5,2)\) from the graph.

Step2: Apply the translation rule

The translation rule is \((x,y)\to(x,y + 3)\).
For point \(A(-5,-3)\), the new - coordinates are \(A'(-5,-3 + 3)=(-5,0)\).
For point \(B(0,0)\), the new - coordinates are \(B'(0,0 + 3)=(0,3)\).
For point \(C(-5,2)\), the new - coordinates are \(C'(-5,2 + 3)=(-5,5)\).

Step3: Plot the new triangle

Plot the points \(A'(-5,0)\), \(B'(0,3)\) and \(C'(-5,5)\) on the coordinate plane and connect them to form the image of \(\triangle ABC\) under the given translation.

Answer:

Plot points \(A'(-5,0)\), \(B'(0,3)\), \(C'(-5,5)\) and connect them to get the translated triangle.