Question

drag the tiles to the correct boxes to complete the pairs.

match the systems of equations with their solution sets.

solution set
\\((-2, 5)\\) and \\((3, -5)\\)
\\((2, 3)\\) and \\((8, 9)\\)
\\((-5, 8)\\) and \\((3, 0)\\)
\\((-2, 3)\\) and \\((7, -6)\\)

linear-quadratic system of equations

tiles:
\\(\

$$\begin{cases} y - 17 = x^2 - 9x \\\\ -x + y = 1 \\end{cases}$$

\\)
\\(\

$$\begin{cases} y - 15 = -x^2 + 4x \\\\ x + y = 1 \\end{cases}$$

\\)
\\(\

$$\begin{cases} y + 5 = x^2 - 3x \\\\ 2x + y = 1 \\end{cases}$$

\\)
\\(\

$$\begin{cases} y + 12 = x^2 + x \\\\ x + y = 3 \\end{cases}$$

\\)

Explanation:

Test the first solution set \((-2, 5)\) and \((3, -5)\)

$$
LATEXBLOCK0
$$

Test the second solution set \((2, 3)\) and \((8, 9)\)

$$
LATEXBLOCK1
$$

Test the remaining solution sets

$$
LATEXBLOCK2
$$

Answer:

Solution Set	Linear-Quadratic System of Equations

| \((-2, 5)\) and \((3, -5)\) | \(

$$\begin{aligned} y + 5 &= x^2 - 3x \\ 2x + y &= 1 \end{aligned}$$

\) |
| \((2, 3)\) and \((8, 9)\) | \(

$$\begin{aligned} y - 17 &= x^2 - 9x \\ -x + y &= 1 \end{aligned}$$

\) |
| \((-5, 8)\) and \((3, 0)\) | \(

$$\begin{aligned} y + 12 &= x^2 + x \\ x + y &= 3 \end{aligned}$$

\) |
| \((-2, 3)\) and \((7, -6)\) | \(

$$\begin{aligned} y - 15 &= -x^2 + 4x \\ x + y &= 1 \end{aligned}$$

\) |