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drag the tiles to the correct boxes to complete the pairs. not all tile…

Question

drag the tiles to the correct boxes to complete the pairs. not all tiles will be used. match each expression to the scenario it represents. expressions: 1.18x, 18/10x, 0.82x, 3/10x, 7/10x, 0.18x scenarios: the price of a game that’s been discounted 18% off its list price (x); the price of a toy that sells for 18% more than the amount (x) needed to build the toy; the volume of water remaining in a tank after 3/10 of its original volume (x) is drained out; the total amount of flour in a bakery after receiving new stock equal to 3/10 of its current stock (x)

Explanation:

Step1: Analyze "18% off list price (x)"

A discount of 18% means we pay \(100\% - 18\% = 82\%\) of \(x\). \(82\% = 0.82\), so the expression is \(0.82x\).

Step2: Analyze "18% more than x"

18% more means \(100\% + 18\% = 118\%\) of \(x\). \(118\% = 1.18\), so the expression is \(1.18x\).

Step3: Analyze "After draining \(\frac{3}{10}\) of x"

Remaining volume is \(x-\frac{3}{10}x=\frac{10 - 3}{10}x=\frac{7}{10}x = 0.7x\)? Wait, no, \(\frac{7}{10}=0.7\)? Wait, no, \(\frac{7}{10}x\) is \(0.7x\)? Wait, no, the tiles have \(\frac{7}{10}x\) and \(\frac{3}{10}x\)? Wait, no, the tiles: \(\frac{3}{10}x\), \(\frac{7}{10}x\), etc. Wait, original volume \(x\), drain \(\frac{3}{10}x\), so remaining is \(x-\frac{3}{10}x=\frac{7}{10}x\).

Step4: Analyze "Receiving \(\frac{3}{10}\) of current stock (x)"

Total flour is \(x+\frac{3}{10}x=\frac{10 + 3}{10}x=\frac{13}{10}x = 1.3x\)? Wait, no, the tiles have \(\frac{13}{10}x\)? Wait, the tiles: \(1.18x\), \(\frac{13}{10}x\) (which is \(1.3x\)), \(0.82x\), \(\frac{3}{10}x\), \(\frac{7}{10}x\), \(0.18x\). Wait, let's re - check:

  1. "18% off x": pay \(1 - 0.18=0.82\) of \(x\), so \(0.82x\).
  1. "18% more than x": \(1 + 0.18 = 1.18\) of \(x\), so \(1.18x\).
  1. "Drain \(\frac{3}{10}\) of x": remaining is \(x-\frac{3}{10}x=\frac{7}{10}x\).
  1. "Receive \(\frac{3}{10}\) of x": total is \(x+\frac{3}{10}x=\frac{13}{10}x\) (since \(\frac{13}{10}=1.3\)? Wait, no, \(\frac{13}{10}x = 1.3x\)? Wait, the tile is \(\frac{13}{10}x\)? Wait, the tiles: \(\frac{13}{10}x\) is one of them? Wait, the given tiles are \(1.18x\), \(\frac{13}{10}x\) (which is \(1.3x\)), \(0.82x\), \(\frac{3}{10}x\), \(\frac{7}{10}x\), \(0.18x\).

So:

  • "18% off x": \(0.82x\)
  • "18% more than x": \(1.18x\)
  • "After draining \(\frac{3}{10}x\)": \(x-\frac{3}{10}x=\frac{7}{10}x\)
  • "After receiving \(\frac{3}{10}x\)": \(x+\frac{3}{10}x=\frac{13}{10}x\)

Answer:

  • the price of a game that's been discounted 18% off its list price (\(x\)): \(0.82x\)
  • the price of a toy that sells for 18% more than the amount (\(x\)) needed to build the toy: \(1.18x\)
  • the volume of water remaining in a tank after \(\frac{3}{10}\) of its original volume (\(x\)) is drained out: \(\frac{7}{10}x\)
  • the total amount of flour in a bakery after receiving new stock equal to \(\frac{3}{10}\) of its current stock (\(x\)): \(\frac{13}{10}x\)