Question

doblan un alambre primero en forma rectangular con 3 in de ancho y 15 in de largo. ¿cuál es la medida de un lado del cuadrado?

Explanation:

Step1: Calculate the perimeter of the rectangle

The perimeter formula of a rectangle is $P = 2(l + w)$. Given $l = 15$ in and $w = 3$ in, then $P=2\times(15 + 3)=2\times18 = 36$ in.

Step2: Find the side - length of the square

The perimeter of a square is $P = 4s$, where $s$ is the side - length. Since the length of the wire is constant (perimeter of rectangle = perimeter of square), we have $4s=36$. Solving for $s$, we get $s=\frac{36}{4}=9$ in.

Answer:

9