Question

if the dna strand read: tacaaatcccctact what would be the genetic code?

2 points

the genetic code (mrna codons)

uuu phe
uuc
uua leu
uug

cuu leu
cuc
cua
cug

auu ile
auc
aua
aug start/met

guu val
guc
gua
gug

ucu ser
ucc
uca
ucg

ccu pro
ccc
cca
ccg

acu thr
acc
aca
acg

gcu ala
gcc
gca
gcg

uau tyr
uac
uaa stop
uag stop

cau his
cac
caa gln
cag

aau asn
aac
aaa lys
aag

gau asp
gac
gaa glu
gag

ugu cys
ugc
uga stop
ugg trp

cgu arg
cgc
cga
cgg

agu ser
agc
aga arg
agg

ggu gly
ggc
gga
ggg

Explanation:

<pre_analysis>
{
"quality": "clear",
"question_count": 1,
"skills_matched": [
"step_cot",
"explain_then_answer",
"tutor",
"mastery_adaptive_brevity"
],
"needs_drawing": false,
"concepts_used": [
"DNA Base Pairing",
"Codon and Anticodon",
"Central Dogma"
],
"new_concepts": [
"Genetic Code Translation"
],
"current_concepts": [
"DNA Base Pairing",
"Codon and Anticodon",
"Central Dogma",
"Genetic Code Translation"
]
}
</pre_analysis>

<reasoning>

Transcribe DNA to mRNA

Using the DNA Base Pairing and Central Dogma knowledge points
\[

$$\begin{aligned} &\text{DNA template strand: } \text{5'-TAC-AAA-TCC-CCT-ACT-3'} \\ &\text{Complementary mRNA: } \text{5'-AUG-UUU-AGG-GGA-UGA-3'} \end{aligned}$$

\]

Group mRNA into codons

Using the Codon and Anticodon knowledge point
\[

$$\begin{aligned} &\text{Codon 1: } \text{AUG} \\ &\text{Codon 2: } \text{UUU} \\ &\text{Codon 3: } \text{AGG} \\ &\text{Codon 4: } \text{GGA} \\ &\text{Codon 5: } \text{UGA} \end{aligned}$$

\]

Translate codons to amino acids

We translate each codon using the provided genetic code table:

• AUG corresponds to start/met (Methionine)
• UUU corresponds to phe (Phenylalanine)
• AGG corresponds to arg (Arginine)
• GGA corresponds to gly (Glycine)
• UGA corresponds to stop (Stop codon)

Determine the final sequence

Combining the translated amino acids in order gives:
\[
\text{met - phe - arg - gly - stop}
\]
</reasoning>

<answer>
met - phe - arg - gly - stop
</answer>

<post_analysis>
{
"subject": "Natural Science",
"question_type": "Fill-in-the-blank",
"knowledge_point": [
"Natural Science",
"Biology",
"Genetic Code Translation"
]
}
</post_analysis>

Answer:

<pre_analysis>
{
"quality": "clear",
"question_count": 1,
"skills_matched": [
"step_cot",
"explain_then_answer",
"tutor",
"mastery_adaptive_brevity"
],
"needs_drawing": false,
"concepts_used": [
"DNA Base Pairing",
"Codon and Anticodon",
"Central Dogma"
],
"new_concepts": [
"Genetic Code Translation"
],
"current_concepts": [
"DNA Base Pairing",
"Codon and Anticodon",
"Central Dogma",
"Genetic Code Translation"
]
}
</pre_analysis>

<reasoning>

Transcribe DNA to mRNA

Using the DNA Base Pairing and Central Dogma knowledge points
\[

$$\begin{aligned} &\text{DNA template strand: } \text{5'-TAC-AAA-TCC-CCT-ACT-3'} \\ &\text{Complementary mRNA: } \text{5'-AUG-UUU-AGG-GGA-UGA-3'} \end{aligned}$$

\]

Group mRNA into codons

Using the Codon and Anticodon knowledge point
\[

$$\begin{aligned} &\text{Codon 1: } \text{AUG} \\ &\text{Codon 2: } \text{UUU} \\ &\text{Codon 3: } \text{AGG} \\ &\text{Codon 4: } \text{GGA} \\ &\text{Codon 5: } \text{UGA} \end{aligned}$$

\]

Translate codons to amino acids

We translate each codon using the provided genetic code table:

• AUG corresponds to start/met (Methionine)
• UUU corresponds to phe (Phenylalanine)
• AGG corresponds to arg (Arginine)
• GGA corresponds to gly (Glycine)
• UGA corresponds to stop (Stop codon)

Determine the final sequence

Combining the translated amino acids in order gives:
\[
\text{met - phe - arg - gly - stop}
\]
</reasoning>

<answer>
met - phe - arg - gly - stop
</answer>

<post_analysis>
{
"subject": "Natural Science",
"question_type": "Fill-in-the-blank",
"knowledge_point": [
"Natural Science",
"Biology",
"Genetic Code Translation"
]
}
</post_analysis>