divide and enter only the remainder!!! (numerator only)
$\frac{x^3 - x^2 - 6}{x + 2}$
note you will need to enter a 0x term for the missing power.
if image does not show: $x^3 - x^2 - 6$ divided by $x + 2$

Question

Accepted Answer

# Explanation:
## Step1: Use Remainder Theorem
The Remainder Theorem states that the remainder of dividing a polynomial $ f(x) $ by $ x - a $ is $ f(a) $. Here, we have $ x + 2 = x - (-2) $, so $ a = -2 $.
First, define the polynomial $ f(x)=x^{3}-x^{2}+0x - 6 $ (adding the missing $ 0x $ term).

## Step2: Substitute $ x=-2 $ into $ f(x) $
$$
\begin{align*}
f(-2)&=(-2)^{3}-(-2)^{2}+0\times(-2)-6\
&=-8 - 4+0 - 6\
&=-12 - 6\
&=-18
\end{align*}
$$

# Answer:
$-18$

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QUESTION IMAGE

Question

Explanation:

Step1: Use Remainder Theorem

Step2: Substitute \( x=-2 \) into \( f(x) \)

Answer: