Question

if the discriminant is greater than 0, the quadratic equation will have
2 real solutions
2 complex solutions
1 real solution

Explanation:

For a quadratic equation \(ax^2 + bx + c = 0\) (\(a
eq0\)), the discriminant is \(D = b^2 - 4ac\). If \(D>0\), the square root of the discriminant in the quadratic formula (\(x=\frac{-b\pm\sqrt{D}}{2a}\)) is a real non - zero number. So, we will get two distinct real values for \(x\) (since we have \(\pm\) in the formula), meaning the quadratic equation has 2 real solutions. If \(D = 0\), we have 1 real solution (a repeated root), and if \(D<0\), we have 2 complex (non - real) solutions.

Answer:

A. 2 real solutions