Question

directions: evaluate the functions below. write your answer in the box below

1. find f(0) when f(x) = -2x + 1
2. find g(8) when g(x) = \frac{1}{4}x

Explanation:

Sub - Question 3:

Step1: Substitute \( x = 0 \) into \( f(x) \)

We have the function \( f(x)=- 2x + 1 \). To find \( f(0) \), we replace \( x \) with \( 0 \) in the function. So we get \( f(0)=-2\times0 + 1 \).

Step2: Simplify the expression

First, calculate \( -2\times0=0 \). Then, \( 0 + 1 = 1 \).

Step1: Substitute \( x = 8 \) into \( g(x) \)

We have the function \( g(x)=\frac{1}{4}x \). To find \( g(8) \), we replace \( x \) with \( 8 \) in the function. So we get \( g(8)=\frac{1}{4}\times8 \).

Step2: Simplify the expression

\( \frac{1}{4}\times8=\frac{8}{4} = 2 \).

Answer:

\( 1 \)

Sub - Question 4: