Question

a diploid cell with 16 chromosomes goes through mitosis. answer the following related to this cell:
a. how many chromatids are present in prophase?
b. how many daughter chromosomes are present during anaphase?
c. how many chromosomes does each daughter cell after cytokinesis?
d. how many chromatids are present in each daughter cell after cytokinesis?

Explanation:

Step1: Determine chromatids in prophase

In prophase of mitosis, each chromosome has two sister chromatids. Given a diploid cell with 16 chromosomes.
Number of chromatids = \(16\times2=32\)

Step2: Determine daughter chromosomes in anaphase

During anaphase, sister chromatids separate and become individual chromosomes (daughter chromosomes). The original cell had 16 chromosomes (each with 2 chromatids). After separation, the number of daughter chromosomes is \(16\times2 = 32\)

Step3: Determine chromosomes in daughter cell after cytokinesis

Mitosis results in two daughter cells that are genetically identical to the parent cell. The parent cell was diploid with 16 chromosomes. Each daughter cell after cytokinesis will have the same number of chromosomes as the parent cell, so 16 chromosomes

Step4: Determine chromatids in daughter cell after cytokinesis

After cytokinesis, in interphase (the phase after mitosis - cytokinesis), chromosomes are in a relaxed state (chromatin). But if we consider the structure, after anaphase separation (and cytokinesis), each chromosome is a single - stranded (no sister chromatids). So the number of chromatids is 0

Answer:

a. 32
b. 32
c. 16
d. 0