Question

in a dihybrid cross for round and yellow seeds (rryy x rryy), what is the probability of having green and wrinkled seeds?
key: r = round
r = wrinkled
y = yellow
y = green
1:16
3:16
8:16
9:16

Explanation:

Step1: Analyze the cross for the seed shape (Rr x Rr)

The possible genotypes for seed shape are RR, Rr, Rr, rr. The probability of getting wrinkled (rr) is $\frac{1}{4}$.

Step2: Analyze the cross for the seed color (Yy x Yy)

The possible genotypes for seed color are YY, Yy, Yy, yy. The probability of getting green (yy) is $\frac{1}{4}$.

Step3: Calculate the combined probability

Using the multiplication rule for independent events, the probability of getting wrinkled and green seeds is $\frac{1}{4}\times\frac{1}{4}=\frac{1}{16}$.

Answer:

1:16