Question

the diagram shows the conservation of mechanical energy. determine the amount of pe and ke at each point pe = 100% a ke = pe = ke = pe = ke = 100% pe = ke =

Explanation:

Step1: Apply the conservation of mechanical energy principle

The total mechanical energy \(E = PE + KE\) is conserved. At point \(A\), since \(PE = 100\%\), then \(KE=0\%\) (because \(E = PE + KE\) and at the highest - point of the ideal mechanical - energy - conservation case, the velocity is \(0\) at \(A\) in this context).

Step2: Analyze point \(B\)

Let the total energy \(E = 100\%\). If we assume a symmetric - like distribution (for a simple non - lossy transfer), if \(PE\) and \(KE\) are splitting the total energy. Since the object is in motion (has \(KE\)) and is at a height (has \(PE\)), if we assume equal - split (a common simple case in basic conservation - of - energy problems without specific height/distance data), \(PE = 50\%\) and \(KE = 50\%\)

Step3: Analyze point \(C\)

At the lowest point (assuming no energy loss), the potential energy \(PE\) is \(0\%\) (taking the lowest - point as the zero - potential - energy level). Then, since \(E=PE + KE\) and \(E = 100\%\), \(KE = 100\%\)

Step4: Analyze point \(D\)

Assume the height at \(D\) is the same as at \(B\) (in a symmetric - like roller - coaster track in an ideal energy - conservation scenario). Then \(PE = 50\%\) and \(KE=50\%\)

Answer:

• \(A\): \(KE = 0\%\)
• \(B\): \(PE = 50\%\), \(KE = 50\%\)
• \(C\): \(PE = 0\%\)
• \(D\): \(PE = 50\%\), \(KE = 50\%\)