QUESTION IMAGE
Question
in the diagram, point n lies on mo. what is the measure of ∠mpn ? 73° 61° 44° 29°
Step1: Find the exterior angle's related angle
The angle at \( N \) is \( 114^\circ \), so its adjacent interior angle (in the triangle) is \( 180^\circ - 114^\circ = 66^\circ \)? Wait, no, wait. Wait, the angle at \( M \) is \( 43^\circ \), and we know that in a triangle, the exterior angle is equal to the sum of the two non - adjacent interior angles. Wait, actually, the angle at \( N \) (the \( 114^\circ \) angle) is an exterior angle of triangle \( MPN \) at vertex \( N \). So, by the exterior angle theorem, \( \angle M + \angle MPN=\angle \text{exterior at } N \). Wait, no, let's correct. The exterior angle at \( N \) (the \( 114^\circ \) angle) is equal to the sum of the two remote interior angles, which are \( \angle M \) and \( \angle MPN \)? Wait, no, \( \angle M \) is \( 43^\circ \), and the exterior angle at \( N \) is \( 114^\circ \). Wait, actually, the angle adjacent to \( 114^\circ \) inside the triangle is \( 180 - 114=66^\circ \)? No, that's not right. Wait, the triangle has angles at \( M \) ( \( 43^\circ \) ), at \( P \) ( \( \angle MPN \), which we need to find), and at \( N \) (the interior angle). The exterior angle at \( N \) is \( 114^\circ \), so the interior angle at \( N \) is \( 180 - 114 = 66^\circ \)? Wait, no, the exterior angle theorem states that the exterior angle is equal to the sum of the two non - adjacent interior angles. So, the exterior angle at \( N \) ( \( 114^\circ \)) is equal to \( \angle M+\angle MPN \)? Wait, \( \angle M = 43^\circ \), so \( 43^\circ+\angle MPN = 114^\circ \)? No, that would give \( \angle MPN=114 - 43 = 71^\circ \), which is not an option. Wait, I must have messed up. Wait, maybe the angle at \( M \) is \( 43^\circ \), and the angle at \( N \) (interior) and the exterior angle. Wait, let's start over.
The sum of angles in a triangle is \( 180^\circ \). Let the interior angle at \( N \) be \( x \). Then \( x = 180 - 114=66^\circ \). Then, in triangle \( MPN \), we have \( \angle M+\angle MPN+\angle N = 180^\circ \). So \( 43^\circ+\angle MPN + 66^\circ=180^\circ \). Then \( \angle MPN=180-(43 + 66)=180 - 109 = 71^\circ \)? No, that's not matching the options. Wait, maybe I got the exterior angle wrong. Wait, the angle at \( M \) is \( 43^\circ \), the exterior angle at \( N \) is \( 114^\circ \). By exterior angle theorem, \( \angle MPN=\text{exterior angle}-\angle M \). Wait, \( 114 - 43 = 71 \), not an option. Wait, the options are \( 73^\circ \), \( 61^\circ \), \( 44^\circ \), \( 29^\circ \). Wait, maybe the angle at \( M \) is \( 43^\circ \), and the exterior angle is \( 114^\circ \), and we need to find \( \angle MPN \). Wait, maybe I made a mistake in the exterior angle. Let's look at the diagram again (mentally). Point \( N \) is on \( MO \), so \( \angle MNO = 114^\circ \), so \( \angle MNP=180 - 114 = 66^\circ \). Then in triangle \( MPN \), angles are \( \angle M = 43^\circ \), \( \angle MNP = 66^\circ \), so \( \angle MPN=180-(43 + 66)=71^\circ \), which is not an option. Wait, maybe the angle at \( M \) is \( 43^\circ \), and the exterior angle is \( 114^\circ \), and the other angle is \( 114 - 43=71 \), no. Wait, the options are \( 73 \), \( 61 \), \( 44 \), \( 29 \). Wait, maybe the angle at \( M \) is \( 43^\circ \), and the exterior angle is \( 114^\circ \), and we have \( \angle MPN=114 - 43 - \) no. Wait, maybe I misread the angle at \( M \). Wait, the angle at \( M \) is \( 43^\circ \), and the exterior angle is \( 114^\circ \). Wait, another approach: the sum of angles in a triangle is \( 180^\circ \). Let \( \angle MPN = x \). The angle at \( N…
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\( 73^\circ \) (corresponding to the first option, A. \( 73^\circ \))