QUESTION IMAGE
Question
determine the equation of the circle graphed below.
Step1: Recall the standard circle equation
The standard form of a circle's equation is \((x - h)^2 + (y - k)^2 = r^2\), where \((h, k)\) is the center and \(r\) is the radius.
Step2: Identify the center of the circle
From the graph, the center of the circle is at \((-6, -4)\) (since it's 6 units left on the x - axis and 4 units down on the y - axis). So \(h=-6\) and \(k = - 4\).
Step3: Determine the radius of the circle
By looking at the grid, the radius (distance from center to any point on the circle) is 2 units (since from \(x=-6\) to \(x = - 4\) or from \(y=-4\) to \(y=-2\) is 2 units). So \(r = 2\), and \(r^{2}=4\).
Step4: Substitute \(h\), \(k\), and \(r^{2}\) into the equation
Substitute \(h=-6\), \(k = - 4\), and \(r^{2}=4\) into \((x - h)^2+(y - k)^2=r^{2}\). We get \((x-(-6))^{2}+(y - (-4))^{2}=4\), which simplifies to \((x + 6)^{2}+(y + 4)^{2}=4\).
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\((x + 6)^{2}+(y + 4)^{2}=4\)