Question

description the midterm exam covers material from chapters 1 - 5. instructions from the list of choices, select the one best answer. multiple attempts not allowed. this test can only be taken once. force completion this test can be saved and resumed later. your answers are saved automatically. question completion status: question 26 a car accelerates from 10.0 m/s to 30.0 m/s at a rate of 3.00 m/s². how far does the car travel while accelerating? 167 m 399 m 80.0 m 226 m 133 m

Explanation:

Step1: Identify the kinematic equation

Use the equation \(v^{2}=v_{0}^{2}+2ax\), where \(v\) is the final velocity, \(v_{0}\) is the initial velocity, \(a\) is the acceleration, and \(x\) is the displacement.

Step2: Rearrange the equation for \(x\)

$$x=\frac{v^{2}-v_{0}^{2}}{2a}$$

Step3: Substitute the given values

Given \(v = 30.0\ m/s\), \(v_{0}=10.0\ m/s\), and \(a = 3.00\ m/s^{2}\)

$$x=\frac{(30.0)^{2}-(10.0)^{2}}{2\times3.00}=\frac{900 - 100}{6.00}=\frac{800}{6.00}\approx133\ m$$

Answer:

133 m