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Question
- density (regular solid): a metal cube has $ell = 2.0$ cm, $w = 2.0$ cm, $h = 2.0$ cm, mass = 16.0 g. find volume and density. will it sink in water? 4. water displacement: a rock raises water from 45.0 ml to 58.5 ml. mass = 20.0 g. find its density. 5. accuracy vs precision: four mass trials give 12.1 g, 12.2 g, 12.1 g, 12.2 g; true mass is 10.0 g. describe accuracy and precision. 6. graph choice: you surveyed favorite snack types in 5 classes. which graph is best and why? 7. line graph slope: temperature rises from 20 $^{circ}$c to 32 $^{circ}$c in 6 min. what is the average rate of change ($^{circ}$c/min)? 8. hypothesis: write an “if...then...because...” hypothesis for how fertilizer concentration affects tomato plant mass.
3.
Step1: Calculate volume of cube
The volume formula for a cube is $V = l\times w\times h$. Given $l = 2.0\ cm$, $w = 2.0\ cm$, $h = 2.0\ cm$, so $V=2.0\times2.0\times2.0 = 8.0\ cm^{3}$.
Step2: Calculate density of cube
The density formula is $
ho=\frac{m}{V}$. Given $m = 16.0\ g$ and $V = 8.0\ cm^{3}$, so $
ho=\frac{16.0\ g}{8.0\ cm^{3}}=2.0\ g/cm^{3}$.
Step3: Determine if it sinks in water
The density of water is approximately $1.0\ g/cm^{3}$. Since $2.0\ g/cm^{3}>1.0\ g/cm^{3}$, the cube will sink.
Step1: Calculate volume of rock
The volume of the rock is equal to the volume of water it displaces. So $V=58.5\ mL - 45.0\ mL=13.5\ mL$. Since $1\ mL = 1\ cm^{3}$, $V = 13.5\ cm^{3}$.
Step2: Calculate density of rock
Using the density formula $
ho=\frac{m}{V}$, with $m = 20.0\ g$ and $V = 13.5\ cm^{3}$, we get $
ho=\frac{20.0\ g}{13.5\ cm^{3}}\approx1.48\ g/cm^{3}$.
Accuracy refers to how close a measurement is to the true - value. Precision refers to how close repeated measurements are to each other. The measured values ($12.1\ g$, $12.2\ g$, $12.1\ g$, $12.2\ g$) are close to each other, so the precision is high. But they are not close to the true mass of $10.0\ g$, so the accuracy is low.
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Volume: $8.0\ cm^{3}$, Density: $2.0\ g/cm^{3}$, It will sink.