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if $mangle2$ is $5x + 5$ degrees and $mangle6$ is $30^{circ}$, what is …

Question

if $mangle2$ is $5x + 5$ degrees and $mangle6$ is $30^{circ}$, what is $x$? $x=$

Explanation:

Step1: Use the property of vertical angles

Vertical angles are equal. So, \(m\angle2 = m\angle6\).

Step2: Set up the equation

Given \(m\angle2=5x + 5\) and \(m\angle6 = 30^{\circ}\), we have the equation \(5x+5=30\).

Step3: Solve the equation for \(x\)

Subtract \(5\) from both sides: \(5x=30 - 5\), so \(5x=25\).
Divide both sides by \(5\): \(x=\frac{25}{5}\).

Answer:

\(x = 5\)