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Question
defining cofunctions: notation
sine and cosine are cofunctions. that is, they are functions that have equal output values (ratios of side lengths) when their input values (______ measures) are complementary angles.
- $sin(\theta)=cos(\\___ -\theta)$
- $cos(\theta)=sin(90-\theta)$
- $sin(60)=cos(\\___)$
exploring cofunctions
use the property of cofunctions to show the equal trigonometric ratios for triangle abc.
angle a and angle b are complementary angles, because $38^\circ$ plus $52^\circ$ is equal to $90^\circ$.
- $sin(\theta)=cos(90-\theta)$
- $sin(38)=\\_______$
- $cos(\theta)=sin(90-\theta)$
- $cos(38)=\\_______$
Step1: Analyze the first blank (input values)
The input values for sine and cosine (trigonometric functions) are angle measures. So the first blank is "angle".
Step2: Analyze \(\sin(\theta)=\cos(\underline{\quad}-\theta)\)
From the cofunction property, we know that \(\sin(\theta)=\cos(90^{\circ}-\theta)\) (since sine and cosine are cofunctions and complementary angles). So the blank here is \(90^{\circ}\) (or \(90\) if degrees are implied).
Step3: Analyze \(\sin(60^{\circ})=\cos(\underline{\quad})\)
Using \(\sin(\theta)=\cos(90^{\circ}-\theta)\), let \(\theta = 60^{\circ}\). Then \(90^{\circ}-\theta=90^{\circ}- 60^{\circ}=30^{\circ}\). So \(\sin(60^{\circ})=\cos(30^{\circ})\), the blank is \(30^{\circ}\) (or \(30\)).
Step4: Analyze \(\sin(38^{\circ})=\underline{\quad}\)
Using \(\sin(\theta)=\cos(90^{\circ}-\theta)\), let \(\theta = 38^{\circ}\). Then \(90^{\circ}-\theta = 90^{\circ}-38^{\circ}=52^{\circ}\). So \(\sin(38^{\circ})=\cos(52^{\circ})\).
Step5: Analyze \(\cos(38^{\circ})=\underline{\quad}\)
Using \(\cos(\theta)=\sin(90^{\circ}-\theta)\), let \(\theta = 38^{\circ}\). Then \(90^{\circ}-\theta=90^{\circ}-38^{\circ} = 52^{\circ}\). So \(\cos(38^{\circ})=\sin(52^{\circ})\).
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- First blank (input values): angle
- \(\sin(\theta)=\cos(\underline{\quad}-\theta)\): \(90^{\circ}\) (or \(90\))
- \(\sin(60^{\circ})=\cos(\underline{\quad})\): \(30^{\circ}\) (or \(30\))
- \(\sin(38^{\circ})=\underline{\quad}\): \(\cos(52^{\circ})\)
- \(\cos(38^{\circ})=\underline{\quad}\): \(\sin(52^{\circ})\)