Question

1. cross a man who is homozygous for brown hair with a woman who is heterozygous for brown hair. what percentage of their children will be blonde?

Explanation:

Step1: Determine the genotypes

Let \( B \) represent the allele for brown hair (dominant) and \( b \) represent the allele for blonde hair (recessive). The man is homozygous for brown hair, so his genotype is \( BB \). The woman is heterozygous for brown hair, so her genotype is \( Bb \).

Step2: Set up the Punnett square

The man can only contribute a \( B \) allele. The woman can contribute either a \( B \) or a \( b \) allele.

	\( B \)	\( B \)
\( b \)	\( Bb \)	\( Bb \)

Step3: Analyze the offspring genotypes

From the Punnett square, the offspring genotypes are \( BB \) and \( Bb \). There are no \( bb \) (blonde - haired) genotypes.

Answer:

0%