QUESTION IMAGE
Question
- ( \triangle cpncong\triangle biy ). identify all pairs of congruent corresponding angles and corresponding sides.
in the diagram below, ( \triangle efgcong\triangle opq ), complete #2 - 7.
- ( overline{ef}cong )____
- ( angle pcong )____
- ( angle gcong )____
- ( mangle o= )____
- ( qo= )____
- ( \triangle gfecong )____
Step1: Use congruent triangle properties
Since \(\triangle EFG\cong\triangle OPQ\), corresponding parts are congruent.
For side \(\overline{EF}\), its corresponding side in \(\triangle OPQ\) is \(\overline{OP}\) (by order of congruence \(E - O\), \(F - P\), \(G - Q\)). So \(\overline{EF}\cong\overline{OP}\).
Step2: For \(\angle P\)
\(\angle P\) corresponds to \(\angle F\) (from \(\triangle EFG\cong\triangle OPQ\)). So \(\angle P\cong\angle F\).
Step3: For \(\angle G\)
\(\angle G\) corresponds to \(\angle Q\). So \(\angle G\cong\angle Q\).
Step4: For \(m\angle O\)
\(\angle O\) corresponds to \(\angle E\). Given \(m\angle E = 110^{\circ}\), so \(m\angle O=110^{\circ}\).
Step5: For \(QO\)
\(QO\) corresponds to \(GE\). Given \(GE = 7\mathrm{km}\), so \(QO = 7\mathrm{km}\).
Step6: For \(\triangle GFE\)
\(\triangle GFE\) (which is same as \(\triangle EFG\)) corresponds to \(\triangle QOP\) (same as \(\triangle OPQ\)). So \(\triangle GFE\cong\triangle QOP\).
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- \(\overline{OP}\)
- \(\angle F\)
- \(\angle Q\)
- \(110^{\circ}\)
- \(7\mathrm{km}\)
- \(\triangle QOP\)