Question

the cosmodock 21 ferris wheel in yokohama city, japan, has a diameter of 100 m. its name comes from its 60 arms, each of which can function as a second hand (so that it makes one revolution every 60.0 s). find the speed of the passengers when the ferris wheel is rotating at this rate. express your answer in meters per second.

Explanation:

Step1: Find the circumference of the Ferris wheel

The formula for the circumference of a circle is \( C = \pi d \), where \( d \) is the diameter. Given \( d = 100 \, \text{m} \), so \( C=\pi\times100 = 100\pi \, \text{m} \).

Step2: Calculate the speed

Speed \( v \) is the distance traveled (circumference) divided by time \( t \). The time for one revolution \( t = 60.0 \, \text{s} \). So \( v=\frac{C}{t}=\frac{100\pi}{60.0} \). Calculating this, \( \frac{100\times3.1416}{60.0}\approx5.24 \, \text{m/s} \) (using \( \pi\approx3.1416 \)).

Answer:

\( \approx5.24 \)