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coordinates (x1, y1) of point d: (-2, -11) coordinates (x2, y2) of poin…

Question

coordinates (x1, y1) of point d: (-2, -11)
coordinates (x2, y2) of point k: (-7, -10)
d = \sqrt{(x2 - x1)^2+(y2 - y1)^2}
d = \sqrt{(5)^2+(-1)^2}
d =
the distance between dontrells house and keikis house is

Explanation:

Step1: Substitute x - values

Given $x_1=-2,x_2 = - 7$, then $x_2 - x_1=-7-(-2)=-7 + 2=-5$. But the value in the box is the absolute - value of this difference, $| - 5| = 5$.

Step2: Substitute y - values

Given $y_1=-11,y_2=-10$, then $y_2 - y_1=-10-(-11)=-10 + 11 = 1$. But the value in the box is $-1$ which might be a calculation error in the provided work. The correct substitution gives $y_2 - y_1 = 1$.

Step3: Calculate the distance

Using the distance formula $d=\sqrt{(x_2 - x_1)^2+(y_2 - y_1)^2}$, substituting $x_2 - x_1=-5$ and $y_2 - y_1 = 1$, we have $d=\sqrt{(-5)^2+1^2}=\sqrt{25 + 1}=\sqrt{26}$.

Answer:

$\sqrt{26}$