Question

the coordinates of the vertices of a triangle are j (1, -2), k (1, 2), and l (-2, 1). triangle jkl is translated 5 units to the right and 4 units down to create triangle jkl as shown in the diagram below. what are the coordinates of the vertices of triangle jkl? j = k =

Explanation:

Step1: Recall translation rule

For a translation 5 units right and 4 units down, the rule is $(x,y)\to(x + 5,y-4)$.

Step2: Find coordinates of $J'$

Given $J(1,-2)$, using the rule: $x=1,y = - 2$, then $x'=1 + 5=6$ and $y'=-2-4=-6$. So $J'=(6,-6)$.

Step3: Find coordinates of $K'$

Given $K(1,2)$, using the rule: $x = 1,y=2$, then $x'=1 + 5=6$ and $y'=2-4=-2$. So $K'=(6,-2)$.

Step4: Find coordinates of $L'$

Given $L(-2,1)$, using the rule: $x=-2,y = 1$, then $x'=-2+5 = 3$ and $y'=1-4=-3$. So $L'=(3,-3)$.

Answer:

$J'=(6,-6)$
$K'=(6,-2)$
$L'=(3,-3)$