QUESTION IMAGE
Question
- $y = 3x + 4$
| $x$ | $y$ |
|---|---|
| $-3$ | |
| $-1$ | |
| $5$ | |
| $9$ |
(coordinate plane grid)
- $y = -2x + 5$
| $x$ | $y$ |
|---|---|
| $-1$ | |
| $1$ | |
| $3$ | |
| $7$ |
(coordinate plane grid)
- $y = 7 - 4x$
| $x$ | $y$ |
|---|---|
| $1$ | |
| $2$ | |
| $3$ | |
| $4$ |
(coordinate plane grid)
- $y = -\frac{4}{5}x + 1$
| $x$ | $y$ |
|---|---|
| $-5$ | |
| $0$ | |
| $5$ | |
| $10$ |
(coordinate plane grid)
- $y = \frac{x}{3} + 2$
| $x$ | $y$ |
|---|---|
(coordinate plane grid)
- $y = -7 - x$
| $x$ | $y$ |
|---|---|
(coordinate plane grid)
(partially visible: $y = \frac{3}{5}x - 2$ with table and grid)
- $y = 5 - \frac{1}{4}x$
| $x$ | $y$ |
|---|---|
(coordinate plane grid)
© gina wilson (all things algebra®, llc), 2016
Let's solve problem 9: \( y = 3x + 4 \) by finding the \( y \)-values for the given \( x \)-values.
Step 1: For \( x = -4 \)
Substitute \( x = -4 \) into the equation \( y = 3x + 4 \).
\( y = 3(-4) + 4 = -12 + 4 = -8 \)
Step 2: For \( x = -3 \)
Substitute \( x = -3 \) into the equation.
\( y = 3(-3) + 4 = -9 + 4 = -5 \)
Step 3: For \( x = -1 \)
Substitute \( x = -1 \) into the equation.
\( y = 3(-1) + 4 = -3 + 4 = 1 \)
Step 4: For \( x = 5 \)
Substitute \( x = 5 \) into the equation.
\( y = 3(5) + 4 = 15 + 4 = 19 \)
Step 5: For \( x = 9 \)
Substitute \( x = 9 \) into the equation.
\( y = 3(9) + 4 = 27 + 4 = 31 \)
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For \( x = -4 \), \( y = -8 \); for \( x = -3 \), \( y = -5 \); for \( x = -1 \), \( y = 1 \); for \( x = 5 \), \( y = 19 \); for \( x = 9 \), \( y = 31 \)
The completed table for problem 9 is:
| \( x \) | \( y \) |
|---|---|
| -3 | -5 |
| -1 | 1 |
| 5 | 19 |
| 9 | 31 |