Question

1. convert the density of gold 19,300 kg/m³ to g/cm³ (1 decimal place).

Explanation:

Step1: Convert kg to g

Since \(1\space kg = 1000\space g\), then \(19300\space kg=19300\times1000 = 19300000\space g\)

Step2: Convert \(m^{3}\) to \(cm^{3}\)

Since \(1\space m = 100\space cm\), then \(1\space m^{3}=(100\space cm)^{3}=1000000\space cm^{3}\)

Step3: Calculate the density in \(g/cm^{3}\)

Density \(d=\frac{19300000\space g}{1000000\space cm^{3}} = 19.3\space g/cm^{3}\)

Answer:

\(19.3\space g/cm^{3}\)