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Question

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student leaves his house and walks 3 meters east, 2 meters south, 3 meters west, and 2 meters north. the
udents trip is shown below.

low far did the student travel and what is the students displacement from the reference point?

Explanation:

Step1: Calculate the total distance traveled

The total distance is the sum of all the individual distances walked.
$$3 + 2+3 + 2$$

Step2: Calculate the displacement

Displacement is a vector quantity. The east - west components: \(3\space m\) east and \(3\space m\) west cancel each other (\(3 - 3=0\)). The north - south components: \(2\space m\) south and \(2\space m\) north cancel each other (\(2 - 2 = 0\)).

Answer:

The student traveled a distance of \(10\space m\) and the displacement is \(0\space m\)