Question

consider the function, $f(x) = 2x - 1$. use the above function to complete the following table. | x | f(x) | | -1 | | | 0 | | | 1 | | | 2 | |

Explanation:

Step1: Substitute \( x = -1 \)

Substitute \( x = -1 \) into \( f(x) = 2x - 1 \). So \( f(-1)=2\times(-1)-1=-2 - 1=-3 \).

Step2: Substitute \( x = 0 \)

Substitute \( x = 0 \) into \( f(x) = 2x - 1 \). So \( f(0)=2\times0 - 1=0 - 1=-1 \).

Step3: Substitute \( x = 1 \)

Substitute \( x = 1 \) into \( f(x) = 2x - 1 \). So \( f(1)=2\times1 - 1=2 - 1 = 1 \).

Step4: Substitute \( x = 2 \)

Substitute \( x = 2 \) into \( f(x) = 2x - 1 \). So \( f(2)=2\times2 - 1=4 - 1 = 3 \).

Answer:

When \( x=-1 \), \( f(x)=-3 \); when \( x = 0 \), \( f(x)=-1 \); when \( x = 1 \), \( f(x)=1 \); when \( x = 2 \), \( f(x)=3 \)

The completed table is:

\( x \)	\( f(x) \)
0	-1
1	1
2	3