Question

consider the following series of arithmetic expressions. int a = 2; int b = 8; int c = 9; ++a; b = a + 27 / c; c /= b - a; system.out.println(a); system.out.println(b); system.out.println(c); what is the output produced by this code? 360 363 330

Explanation:

Step1: Increment a

The ++a is a pre - increment operation. So \(a = 2+1=3\).

Step2: Calculate b

We know \(a = 3\) and \(c = 9\). Using the formula \(b=a + 27/c\), substitute the values: \(b=3+\frac{27}{9}\). Since \(\frac{27}{9}=3\), then \(b = 3 + 3=6\).

Step3: Calculate c

We know \(b = 6\) and \(a = 3\). The operation \(c/=b - a\) is equivalent to \(c=c/(b - a)\). Substitute the values: \(c=\frac{9}{6 - 3}\). Since \(6-3 = 3\), then \(c=\frac{9}{3}=3\).

Answer:

The output of System.out.println(a); is \(3\), the output of System.out.println(b); is \(6\), and the output of System.out.println(c); is \(3\). But if we assume that there was a mistake in the problem statement (maybe the intended code was to print \(a*b*c\)), \(a\times b\times c=3\times6\times3 = 54\). However, based on the standard output of each println statement:

• System.out.println(a); → \(3\)
• System.out.println(b); → \(6\)
• System.out.println(c); → \(3\)