Question

1. consider the diagram of a portable soccer goal. the black lines show the frame of the goal.

how many feet of framing are needed for the frame of the goal? round to the nearest tenth
of a foot.

Explanation:

Step1: Identify shape components

The frame has 2 right triangles, 2 rectangles, and 2 parallelograms.

Step2: Calculate triangle hypotenuse

Right triangle legs: 5ft, 6ft.
Hypotenuse: $\sqrt{5^2 + 6^2} = \sqrt{25 + 36} = \sqrt{61} \approx 7.81$ ft.

Step3: Count frame edges

• Vertical sides: 2×6ft = 12ft
• Base sides: 2×5ft = 10ft
• Hypotenuses: 2×7.81ft ≈15.62ft
• Top/bottom rectangles: 2×10ft =20ft

Step4: Sum all edges

Total framing: $12 + 10 + 15.62 + 20 = 57.62$ ft.

Step5: Round to nearest tenth

$57.62 \approx 57.6$ ft.

Answer:

57.6