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is \\( \\triangle mno \\) congruent to \\( \\triangle vwx \\)? justify …

Question

is \\( \triangle mno \\) congruent to \\( \triangle vwx \\)? justify your answer using rigid motions.

yes. a dilation and a reflection can map \\( \triangle mno \\) onto \\( \triangle vwx \\).

yes. a translation and a rotation can map \\( \triangle mno \\) onto \\( \triangle vwx \\).

no. it is not possible to map \\( \triangle mno \\) onto \\( \triangle vwx \\) using only rigid motions.

Explanation:

Step1: Analyze the angles of the triangles

In \(\triangle MNO\), the angles are \(35^{\circ}\), \(90^{\circ}\), and \(55^{\circ}\). In \(\triangle VWX\), the angles are \(30^{\circ}\), \(90^{\circ}\), and \(60^{\circ}\).

Step2: Recall the property of rigid motions

Rigid motions (translation, rotation, reflection) preserve the shape and size of a figure, including the measures of angles.

Step3: Compare the angle measures

Since the sets of angle measures (\(35^{\circ},90^{\circ},55^{\circ}\) vs \(30^{\circ},90^{\circ},60^{\circ}\)) are different, the triangles are not congruent. Rigid motions cannot change angle measures.

Answer:

No. It is not possible to map \(\triangle MNO\) onto \(\triangle VWX\) using only rigid motions.