Question

1. (cone with radius 4 m, height 10 m) 2. (cone with radius 2 cm, height 7 cm) 3. (cone with slant height 5 m, height 15 mm) 4. (cone with radius 6 cm, height 7 cm) 5. (cone with height 23 m, radius 10 m) 6. (cone with radius 5 mm, height 6 mm)

Explanation:

Since the problem involves cones and likely calculating their volume or surface area (common in Geometry), we'll use the formula for the volume of a cone, \( V = \frac{1}{3}\pi r^2 h \), where \( r \) is the radius and \( h \) is the height. Let's take the first cone (1.) as an example: radius \( r = 4 \, \text{m} \), height \( h = 10 \, \text{m} \).

Step1: Identify \( r \) and \( h \)

For cone 1: \( r = 4 \, \text{m} \), \( h = 10 \, \text{m} \)

Step2: Apply the volume formula

\( V = \frac{1}{3}\pi (4)^2 (10) = \frac{1}{3}\pi \times 16 \times 10 = \frac{160}{3}\pi \approx 167.55 \, \text{m}^3 \)

(If the problem was about another cone, adjust \( r \) and \( h \) accordingly. For example, cone 2: \( r = 2 \, \text{cm} \), \( h = 7 \, \text{cm} \), \( V = \frac{1}{3}\pi (2)^2 (7) = \frac{28}{3}\pi \approx 29.32 \, \text{cm}^3 \))

Answer:

For cone 1 (radius 4 m, height 10 m), the volume is \( \frac{160}{3}\pi \, \text{m}^3 \) (or approximately \( 167.55 \, \text{m}^3 \)). (Adjust based on the specific cone in question.)