Question

conclusion: how are mass, volume, and density related? density mass mass matter property space takes up unknown volume volume volume claim: density is a ratio of mass and volume. it can be used to identify unkown substances. evidence: table with columns: mass of liquid (g), volume (ml), density (g/ml³), substance; rows: liquid a, liquid b, liquid c (each with volume 10 ml and \type answer\ for mass of liquid, density, substance) reasoning: density is a property of matter. it is calculated using a known mass and volume. mass is the amount of matter in something. volume is the amount of space that a substance occupies.

Explanation:

To solve for the density, mass, and identify the substance, we use the formula for density:

Step 1: Recall the density formula

The formula for density ($
ho$) is $
ho = \frac{\text{mass (}m\text{)}}{\text{volume (}V\text{)}}$, where mass is in grams (g) and volume is in milliliters (mL) (or cubic centimeters, since $1\ \text{mL} = 1\ \text{cm}^3$).

Step 2: Calculate density for each liquid

For a liquid with a known mass ($m$) and volume ($V = 10\ \text{mL}$), substitute into the formula. For example:

• If Liquid A has a mass of $10\ \text{g}$:

$
ho = \frac{10\ \text{g}}{10\ \text{mL}} = 1\ \text{g/mL}$.
(This density matches water, so the substance might be water.)

• If Liquid B has a mass of $8\ \text{g}$:

$
ho = \frac{8\ \text{g}}{10\ \text{mL}} = 0.8\ \text{g/mL}$.
(This density is typical of rubbing alcohol or oil.)

• If Liquid C has a mass of $12\ \text{g}$:

$
ho = \frac{12\ \text{g}}{10\ \text{mL}} = 1.2\ \text{g/mL}$.
(This density could match a salt solution or honey.)

Step 3: Identify the substance

Compare the calculated density to known densities of substances. For example:

• Density of water: $1\ \text{g/mL}$
• Density of rubbing alcohol: $\approx 0.78\ \text{g/mL}$ (close to $0.8\ \text{g/mL}$)
• Density of honey: $\approx 1.4\ \text{g/mL}$ (close to $1.2\ \text{g/mL}$ for a less concentrated solution)

Example Completion (using sample masses):

Liquid	Mass (g)	Volume (mL)	Density (g/mL)	Substance
B	$8$	$10$	$0.8$	Rubbing Alcohol
C	$12$	$10$	$1.2$	Salt Solution

Key Relationships:

• Density is a physical property of matter, calculated as $\boldsymbol{

ho = \frac{m}{V}}$.

• Mass is the amount of matter in a substance.
• Volume is the space a substance occupies.
• Density helps identify unknown substances because each pure substance has a unique density (at a given temperature/pressure).

If you have specific masses for the liquids, substitute them into the density formula to find the exact density and match it to a known substance!

Answer:

To solve for the density, mass, and identify the substance, we use the formula for density:

Step 1: Recall the density formula

The formula for density ($
ho$) is $
ho = \frac{\text{mass (}m\text{)}}{\text{volume (}V\text{)}}$, where mass is in grams (g) and volume is in milliliters (mL) (or cubic centimeters, since $1\ \text{mL} = 1\ \text{cm}^3$).

Step 2: Calculate density for each liquid

For a liquid with a known mass ($m$) and volume ($V = 10\ \text{mL}$), substitute into the formula. For example:

• If Liquid A has a mass of $10\ \text{g}$:

$
ho = \frac{10\ \text{g}}{10\ \text{mL}} = 1\ \text{g/mL}$.
(This density matches water, so the substance might be water.)

• If Liquid B has a mass of $8\ \text{g}$:

$
ho = \frac{8\ \text{g}}{10\ \text{mL}} = 0.8\ \text{g/mL}$.
(This density is typical of rubbing alcohol or oil.)

• If Liquid C has a mass of $12\ \text{g}$:

$
ho = \frac{12\ \text{g}}{10\ \text{mL}} = 1.2\ \text{g/mL}$.
(This density could match a salt solution or honey.)

Step 3: Identify the substance

Compare the calculated density to known densities of substances. For example:

• Density of water: $1\ \text{g/mL}$
• Density of rubbing alcohol: $\approx 0.78\ \text{g/mL}$ (close to $0.8\ \text{g/mL}$)
• Density of honey: $\approx 1.4\ \text{g/mL}$ (close to $1.2\ \text{g/mL}$ for a less concentrated solution)

Example Completion (using sample masses):

Liquid	Mass (g)	Volume (mL)	Density (g/mL)	Substance
B	$8$	$10$	$0.8$	Rubbing Alcohol
C	$12$	$10$	$1.2$	Salt Solution

Key Relationships:

• Density is a physical property of matter, calculated as $\boldsymbol{

ho = \frac{m}{V}}$.

• Mass is the amount of matter in a substance.
• Volume is the space a substance occupies.
• Density helps identify unknown substances because each pure substance has a unique density (at a given temperature/pressure).

If you have specific masses for the liquids, substitute them into the density formula to find the exact density and match it to a known substance!