Question

complete the square and write the given equation in standard form. then give the center and radius of the circle and graph the equation.
$x^{2}-8x + y^{2}-9 = 0$
the equation in standard form is $(x - 4)^{2}+y^{2}=25$.
(simplify your answer.)
the center of the circle is
(type an ordered pair.)

Explanation:

Step1: Recall the standard form of a circle equation

The standard form of a circle equation is \((x - h)^2+(y - k)^2=r^2\), where \((h,k)\) is the center and \(r\) is the radius.

Step2: Identify \(h\) and \(k\) from the given standard - form equation \((x - 4)^2+y^2 = 25\)

Compare \((x - 4)^2+(y - 0)^2=5^2\) with \((x - h)^2+(y - k)^2=r^2\).

Answer:

The center of the circle is \((4,0)\)